x^2+3x+2.25=1.25

Solution for x^2+3x+2.25=1.25 equation:

x^2+3x+2.25=1.25

We move all terms to the left:

x^2+3x+2.25-(1.25)=0

We add all the numbers together, and all the variables

x^2+3x+1=0

a = 1; b = 3; c = +1;
Δ = b2-4ac
Δ = 32-4·1·1
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{5}}{2*1}=\frac{-3-\sqrt{5}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{5}}{2*1}=\frac{-3+\sqrt{5}}{2}
$